网站页面
当前课程
成员
General
主题 1
主题 2
主题 4
主题 5
主题 6
主题 7
主题 8
主题 9
主题 10
主题 11
主题 12
主题 13
主题 14
主题 15
主题 16
主题 17
主题 18
主题 19
主题 20
[POJ1401]阶乘
成绩 | 0 | 开启时间 | 2013年02月21日 星期四 23:02 |
折扣 | 0.8 | 折扣时间 | 2013年02月28日 星期四 23:02 |
允许迟交 | 是 | 关闭时间 | 2013年02月28日 星期四 23:02 |
输入文件 | fact.in | 输出文件 | fact.out |
POJ 1401
求N!中末尾0的个数。
Description
Input
Output
Sample Input
Sample Output
Source
Time Limit: 1500MS
Memory Limit: 65536K
Total Submissions: 12309
Accepted: 7673
ACM technicians faced a very interesting problem recently. Given a set of BTSes to visit, they needed to find the shortest path to visit all of the given points and return back to the central company building. Programmers have spent several months studying this problem but with no results. They were unable to find the solution fast enough. After a long time, one of the programmers found this problem in a conference article. Unfortunately, he found that the problem is so called "Travelling Salesman Problem" and it is very hard to solve. If we have N BTSes to be visited, we can visit them in any order, giving us N! possibilities to examine. The function expressing that number is called factorial and can be computed as a product 1.2.3.4....N. The number is very high even for a relatively small N.
The programmers understood they had no chance to solve the problem. But because they have already received the research grant from the government, they needed to continue with their studies and produce at least some results. So they started to study behaviour of the factorial function.
For example, they defined the function Z. For any positive integer N, Z(N) is the number of zeros at the end of the decimal form of number N!. They noticed that this function never decreases. If we have two numbers N1 < N2, then Z(N1) <= Z(N2). It is because we can never "lose" any trailing zero by multiplying by any positive number. We can only get new and new zeros. The function Z is very interesting, so we need a computer program that can determine its value efficiently.
6
3
60
100
1024
23456
8735373
0
14
24
253
5861
2183837